It is well known that the universe is not a chaotic system but governed by laws that are predictable. All of creation exhibits order. The Fibonacci series and the ‘golden numbers’ are found in all ordered and stable components of all living and non living things.

https://tallbloke.wordpress.com/2013/02/20/a-remarkable-discovery-all-solar-system-periods-fit-the-fibonacci-series-and-the-golden-ratio-why-phi/

So why wouldn’t we find Fibonacci numbers in the weather and earths climate.

I have started this post on Tom Mangos request and posted his table of Fibonacci and conjunction cycles as requested. Tom studies the sun, moon and the large planets Jupiter and Saturn and there links to the earths climate .

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Thanks Tom for your table of fibonacci numbers in relation to conjunction cycles. Please could you explain the table and assume readers no nothing. Thankyou.

I have kept the title of the post broad and linked to weather in keeping with the title of my blog. Cycles and the weather/climate.

l look forward to reading . Please feel free to contribute

not quite climate but..

correlations of planets rotation around the sun and the arrangement of leaves on plants

In the area of very large phenomena when the time period of each planet’s revolution around the sun is compared in round numbers to the one adjacent to it, their fractions are Fibonacci numbers! Beginning with Neptune and moving inward toward the sun, the ratios are 1/2, 1/3, 2/5, 3/8, 5/13, 8/21, 13/34. These are the same as the spiral arrangement of leaves on plants!

Revolution of the planets in days and their correlation to

Fibonacci numbers and spiral arrangement of leaves on plants

check out the numbers on this site here

http://www.icr.org/article/shapes-numbers-patterns-divine-proportion-gods-cre/

Hi Sue,

Thanks for posting my table. Please forgive any

misuse of terminology on my part. By Fibonacci

numbers I’m referring to the sequence of numbers

that are the sum of the two previous numbers.

In spite of my very limited knowledge of Phi and the

Fibonacci sequence, it is well known that they can be

found everywhere in nature. We should be able to see

them in the sun’s motion around the solar system’s

center of mass.

In the table above I refer to special conjunction cycles.

The sun’s acceleration takes place between the opposition

of Jupiter/Saturn and the alignment of Jupiter/Saturn. So, the

alignment of Jupiter/Saturn only signifies the end of the

acceleration which takes place over this ~9.929 year period.

During an ice age Jupiter and Saturn still align but the

acceleration of the sun is substantially diminished. The sun’s

acceleration is overwhelmingly inherited from the accelerations

of the gas giants. When the gas giants lose their eccentricity

they and the sun lose their acceleration. It is the acceleration

of the sun that is responsible for strong magnetic fields throughout

the solar system. Force does not equal [mass x alignment].

During an inter-glacial period the sun orbits the center of mass

in a wide looping pattern. When the sun decelerates it moves

in closer to the center of mass. When the sun accelerates it pulls

away from the center of mass. The sun has an inwardly directed

deceleration and an outwardly directed acceleration.

Our solar system is regulated by the 360 degree rotation of the

sun’s outwardly directed acceleration. The frequencies listed in

the table above have this 360 degree rotation.

continued . . .

using: . . . . . . J = 11.862242 . . . . . . . . . . . S = 29.457784

Jupiter is approximately 72% of the mass orbiting the Sun. Because of

this, Jupiter and the Sun share a binary attribute, they always oppose one

another. Jupiter is a massive planet, but this is more about percentages

than about mass. To share this binary attribute with the Sun, a planet need

only be more than 50% of the mass orbiting the Sun. Saturn is approximately

21% of the mass, so consequently Saturn will be regularly found on the

same side of the center of mass as our Sun. But… if we were to remove Jupiter

from our solar system, Saturn would then be 66+% of the mass and would

develop a similar binary relationship with the Sun. Our sun would no longer

orbit the center of mass in 11.862242 years but in 29.457784 years.

The Sun’s orbital pattern is not usually viewed as an 11.862242 year 360 degree

trip around the center of mass. The Sun orbits the center of mass in a looping

pattern called an epi-trochiod which is a 19.8593122389 year 602.6982425434

degree excursion.

. . . . (19.8593122389 / 11.862242) 360 deg = 602.6982425434 deg.

. . . . . . . 602.6982425434 deg – 360 deg = 242.6982425434 deg

The Sun’s pattern of motion rotates ~242.6982425434 degrees in a

counter-clockwise direction every 19.8593122389 years (Jupiter/Saturn

synodic period). This could also be viewed as an ~117.30175745651 degree

clockwise rotation.

Because they are separated by ~117.30175745651 degrees, three successive

synodic loops form the distinct shape of a three leaf clover. But this tri-synodic

period of 59.57793671687 years does not complete a full 360 degree

rotation.

. . . . . . . . 360 deg – (117.30175745651 deg) 3 = 8.09472763044 deg

Each successive tri-synodic pattern rotates ~8.09472763044 degrees in

a counter-clockwise direction every 59.57793671687 years, eventually

turning 360 degrees in 2649.63297065 years.

(360 deg / 8.09472763044 deg) 59.57793671687 = 2649.63297065322 yrs

We could also have calculated the number of years that

pass with each degree of rotation:

. . . . . 59.57793671687 / 8.09472763044 deg = 7.360091586 years/deg

. . . . . (7.360091586 years/deg) 360 deg = 2649.63297065322 years

The 2649.63297065322 year cycle belongs to an exclusive group of

frequencies that have a 360 degree rotation characteristic. There’s a

patterned formula for viewing these frequencies in pairs and the

2649.63297065322 year cycle is one of these significant periods.

continued . . .

using: . . . . . J = 11.862242 . . . . . . . S = 29.457784 . . . . . . .

There is an exclusive group of frequencies that have a 360 degree

rotation characteristic. We can view these frequencies in pairs with

these formulas:

. . . (a) 19.8593122389 x N x 360 / (117.3017574565 x N – 360 x M)

. . . (b) 19.8593122389 x N x 360 / (242.6982425434 x N – 360 x M)

. . . where: 360 x M reduces the denominator so as to fall within

. . . a range of 0 to 360 degrees

when N = {3, 6, 9, 12, 15, . . . 132} using formula (b) we get

2649.63297065322 years

when N = {2, 4} using formula (b) we get 114.02975542582 years

when N = {1, 2, 3} using formula (a) we get 60.94838271 years

when N = {43, 86, 129, 172, . . .} using formula (a) we get

77327.805752832 years = 1798.321064019 (43) ‘ Keeling & Whorf

77327.805752832 years = 25775.935290544 (3) ‘ axial precession

If we take the first N from each set we can find the root of any

period that is derived from using formulas (a) and (b):

2649.63297065322 / 3 = . (J / 2)(S / 5) / (J / 2 – S / 5)

114.02975542582 / 2 = . . J (S / 3) / (J – S / 3)

60.9483827100845 / 1 = . (S / 2) J / (S / 2 – J)

77327.805752832 / 43 = . (S / 72)(J / 29) / (S / 72 – J / 29)

When N = {132, 264, 396, . . .} using formula (a) we get

246273.06727448875 years = 1865.70505510976 (132)

1865.70505510976 (22) = 41045.51121241479 years ‘ obliquity

246273.06727448875 / 132 = (S / 221)(J / 89) / (S / 221 – J / 89)

The 2649.63297065322 and the 77327.805752832 year cycles

are contained in the Fibonacci table above. They are members

of an exclusive group of frequencies that display a 360 degree

rotation of the sun’s outwardly directed acceleration.

. . . . continued . . .

using: . . . . . J = 11.862242 . . . . S = 29.457784 . . . . .

. . (a) 19.8593122389 x N x 360 / (117.3017574565 x N – 360 x M)

. . (b) 19.8593122389 x N x 360 / (242.6982425434 x N – 360 x M)

. . . where: 360 x M reduces the denominator so as to fall within

. . . a range of 0 to 360 degrees

when N = {46, 92, 138, 184 . . .} using formula (b) we get

79839.2026981547 years = 1735.6348412642 (46)

79839.2026981547 / 46 = (J / 31)(S / 77) / (J / 31 – S / 77)

when N = {89, 178, 267, . . . } using formula (b) we get

4431425.94338327044742 years = 49791.302734643488 (89)

49791.302734643488 (2) = 99582.605469286976 years ‘ earth’s eccentric orbit

4431425.94338327044742 / 89 = (J / 60)(S / 149) / (J / 60 – S / 149)

when N = {135, 270, 405 . . .} using formula (b) we get

226418.1751199113 years = 1677.17166755489 (135)

1677.17166755489 (135/2) = 113209.08755995565 years ‘ precession of perihelion

226418.1751199113 / 135 = (J / 91)(S / 226) / (J / 91 – S / 226)

The 79839.2026981547, 4431425.94338327044 and 226418.1751199113

year cycles are contained in the Fibonacci table above. They are members

of an exclusive group of frequencies that exhibit a 360 degree

rotation of the sun’s outwardly directed acceleration.

. . . . continued . . .

. . . . . . J = 11.862242 . . . . . . . S = 29.457784 . . . . . .

(1622.5187011493 yrs.) 224 = 363444.189057451 yrs.

(1677.1716675548 yrs.) 135 = 226418.1751199113 yrs.

(1735.6348412642 yrs.) 46 = 79839.2026981547 yrs.

(1798.3210640193 yrs.) 43 = 77327.805752832 yrs.

(1865.7050551097 yrs.) 132 = 246273.06727448875 yrs.

(49791.302734643 yrs.) 89 = 4431425.94338327044742 yrs.

It is widely accepted that because the Milankovic cycles describe

motions of the earth that these cycles are “earth’s cycles”. But

this is simply not true. The Milankovic cycles are the sole property

of the sun and all of the sun’s satellites feel the same accelerations

of the sun and this includes the four gas giants.

The largest of these cycles, listed above, is the 4431425.94338327044742

year cycle (49791.302734643 x 89). The earth’s eccentric orbit expands

and contracts to a 99582.6054692869 year cycle (49791.302734643 x 2).

This particular period is unique among the others because of its direct link

to eccentricity. Where there is eccentricity there is acceleration. The

Milankovic cycles belong to the sun and they all point to the large

eccentricity cycle:

where: . . . . . . . . P3 = P1 x P2 / (P1 – P2)

. . . . . P1 . . . . . . . . . . . . . . P2 . . . . . . . . . . . . . . P3 . . . . . . . . .

1677.1716675548 ‘ ‘ ‘ ‘ ‘ 1622.5187011493 ‘ ‘ ‘ ‘ ‘ 49791.302734643

1735.6348412642 ‘ ‘ ‘ ‘ ‘ 1677.1716675548 ‘ ‘ ‘ ‘ ‘ 49791.302734643

1798.3210640193 ‘ ‘ ‘ ‘ ‘ 1735.6348412642 ‘ ‘ ‘ ‘ ‘ 49791.302734643

1865.7050551097 ‘ ‘ ‘ ‘ ‘ 1798.3210640193 ‘ ‘ ‘ ‘ ‘ 49791.302734643

. . . . . . continued . . .

I’d recommend NASA/JPL planetary data as opposed to the NASA factsheets e.g. Saturn orbit period is different.

http://solarsystem.nasa.gov/multimedia/downloads/13_Saturn_FC1.pdf

At a glance: http://ssd.jpl.nasa.gov/?planet_phys_par

OB,

Thanks for bringing up the Saturn orbital period issue.

I’ve commented on this in an earlier thread. I’ll just re-post

it here so you don’t have to look for it:

The orbital periods for Jupiter and Saturn have some irregularity about

them, so there is a lot of disagreement about their exact values. Surprisingly

there really isn’t as much room for tweaking these numbers as some would

believe. The exact number of days is pretty solid, it’s the additional hours

that are causing fights to break out. It is important that we address this

issue before we move on.

The best values can be found at: nssdc.gsfc.nasa.gov/planetary/factsheet

by author Dr David R. Williams: using sidereal periods S = 29.457 and

J = 11.862.

Avoid using: the data at ssd.jpl.nasa.gov/?planet_phys_par

This data had a mislabeling problem in which the tropical periods were

listed as sidereal. An attempt to correct the problem resulted in a

period of S = 29.447 years sidereal and S = 29.42351935 tropical.

The Williams data at nssdc.gsfc also had a tropical period of S = 29.424

years, suggesting that the ssd.jpl sidereal period of S = 29.447 is most

likely a typo.

Like I said earlier, there isn’t a lot of room for this much error. The difference

between the sidereal values of 29.447 (ssd.jpl) and 29.457 (nssdc.gsfc)

would be more than 3 and a half days, an obvious typo.

OB,

I don’t know where that anonymous came from.

I’d like to hear what you have to say about the Fibonacci

sequence.

Hi Sue,

I’d like to post a couple more graphs for

clarification (10 / 4 . . e-mail). Thanks so much.

Here are some more graphs TOM MANGO has asked me to post for discussion

Unfortunately the comment section doesn’t seem to support large pictures Tom.

Readers may have to click on this link to the original storage point

when the picture loads . you may have to click on it to load the larger zoomed image

https://goo.gl/photos/ejD1y2LjFw4Jc6ZX7

or try th😓s link

https://photos.google.com/share/AF1QipPDhiGZmzUFLOUeaWveNvd-3a8Qn5T3X6okCnDkY1Q3YhUXh8W-zMVpM9D5YoZ78Q/photo/AF1QipMdomgXaVI9ozH02RxHeyOL6Ja3hrFpb5CYm02j?key=bXB0OEhsRGZlbktQbmJRSk1kVklZQ0oyVHhDYTlR

next 3 frames

click this link for the original and zoomed image

https://photos.google.com/photo/AF1QipO5Q3zyB3X2A8Fmz1yBiPylm9vwopYsr37SevPr

a link from tallbloke on Fibonacci and the solar system

https://tallbloke.wordpress.com/2013/02/20/a-remarkable-discovery-all-solar-system-periods-fit-the-fibonacci-series-and-the-golden-ratio-why-phi/