Image

Fibonacci and the earths climate

It is well known that the universe is not a chaotic system but governed by laws that are predictable. All of creation exhibits order. The Fibonacci series and the ‘golden numbers’ are found in all ordered and stable components of all living and non living things.

https://tallbloke.wordpress.com/2013/02/20/a-remarkable-discovery-all-solar-system-periods-fit-the-fibonacci-series-and-the-golden-ratio-why-phi/

So why wouldn’t we find Fibonacci numbers in the weather and earths climate.

I have started this post on Tom Mangos request and posted his table of Fibonacci and conjunction cycles as requested. Tom studies the sun, moon  and the large planets Jupiter and Saturn and  there links to the earths climate .

fibonacci_1and-conjunctipn-cycles

 

 

Advertisements

14 comments on “Fibonacci and the earths climate

  1. Thanks Tom for your table of fibonacci numbers in relation to conjunction cycles. Please could you explain the table and assume readers no nothing. Thankyou.

    I have kept the title of the post broad and linked to weather in keeping with the title of my blog. Cycles and the weather/climate.
    l look forward to reading . Please feel free to contribute

  2. not quite climate but..

    correlations of planets rotation around the sun and the arrangement of leaves on plants

    In the area of very large phenomena when the time period of each planet’s revolution around the sun is compared in round numbers to the one adjacent to it, their fractions are Fibonacci numbers! Beginning with Neptune and moving inward toward the sun, the ratios are 1/2, 1/3, 2/5, 3/8, 5/13, 8/21, 13/34. These are the same as the spiral arrangement of leaves on plants!

    Revolution of the planets in days and their correlation to
    Fibonacci numbers and spiral arrangement of leaves on plants
    check out the numbers on this site here
    http://www.icr.org/article/shapes-numbers-patterns-divine-proportion-gods-cre/

  3. Hi Sue,
    Thanks for posting my table. Please forgive any
    misuse of terminology on my part. By Fibonacci
    numbers I’m referring to the sequence of numbers
    that are the sum of the two previous numbers.

    In spite of my very limited knowledge of Phi and the
    Fibonacci sequence, it is well known that they can be
    found everywhere in nature. We should be able to see
    them in the sun’s motion around the solar system’s
    center of mass.

    In the table above I refer to special conjunction cycles.
    The sun’s acceleration takes place between the opposition
    of Jupiter/Saturn and the alignment of Jupiter/Saturn. So, the
    alignment of Jupiter/Saturn only signifies the end of the
    acceleration which takes place over this ~9.929 year period.
    During an ice age Jupiter and Saturn still align but the
    acceleration of the sun is substantially diminished. The sun’s
    acceleration is overwhelmingly inherited from the accelerations
    of the gas giants. When the gas giants lose their eccentricity
    they and the sun lose their acceleration. It is the acceleration
    of the sun that is responsible for strong magnetic fields throughout
    the solar system. Force does not equal [mass x alignment].

    During an inter-glacial period the sun orbits the center of mass
    in a wide looping pattern. When the sun decelerates it moves
    in closer to the center of mass. When the sun accelerates it pulls
    away from the center of mass. The sun has an inwardly directed
    deceleration and an outwardly directed acceleration.

    Our solar system is regulated by the 360 degree rotation of the
    sun’s outwardly directed acceleration. The frequencies listed in
    the table above have this 360 degree rotation.

    continued . . .

  4. using: . . . . . . J = 11.862242 . . . . . . . . . . . S = 29.457784
    Jupiter is approximately 72% of the mass orbiting the Sun. Because of
    this, Jupiter and the Sun share a binary attribute, they always oppose one
    another. Jupiter is a massive planet, but this is more about percentages
    than about mass. To share this binary attribute with the Sun, a planet need
    only be more than 50% of the mass orbiting the Sun. Saturn is approximately
    21% of the mass, so consequently Saturn will be regularly found on the
    same side of the center of mass as our Sun. But… if we were to remove Jupiter
    from our solar system, Saturn would then be 66+% of the mass and would
    develop a similar binary relationship with the Sun. Our sun would no longer
    orbit the center of mass in 11.862242 years but in 29.457784 years.

    The Sun’s orbital pattern is not usually viewed as an 11.862242 year 360 degree
    trip around the center of mass. The Sun orbits the center of mass in a looping
    pattern called an epi-trochiod which is a 19.8593122389 year 602.6982425434
    degree excursion.
    . . . . (19.8593122389 / 11.862242) 360 deg = 602.6982425434 deg.
    . . . . . . . 602.6982425434 deg – 360 deg = 242.6982425434 deg

    The Sun’s pattern of motion rotates ~242.6982425434 degrees in a
    counter-clockwise direction every 19.8593122389 years (Jupiter/Saturn
    synodic period). This could also be viewed as an ~117.30175745651 degree
    clockwise rotation.

    Because they are separated by ~117.30175745651 degrees, three successive
    synodic loops form the distinct shape of a three leaf clover. But this tri-synodic
    period of 59.57793671687 years does not complete a full 360 degree
    rotation.

    . . . . . . . . 360 deg – (117.30175745651 deg) 3 = 8.09472763044 deg

    Each successive tri-synodic pattern rotates ~8.09472763044 degrees in
    a counter-clockwise direction every 59.57793671687 years, eventually
    turning 360 degrees in 2649.63297065 years.

    (360 deg / 8.09472763044 deg) 59.57793671687 = 2649.63297065322 yrs

    We could also have calculated the number of years that
    pass with each degree of rotation:
    . . . . . 59.57793671687 / 8.09472763044 deg = 7.360091586 years/deg
    . . . . . (7.360091586 years/deg) 360 deg = 2649.63297065322 years

    The 2649.63297065322 year cycle belongs to an exclusive group of
    frequencies that have a 360 degree rotation characteristic. There’s a
    patterned formula for viewing these frequencies in pairs and the
    2649.63297065322 year cycle is one of these significant periods.

    continued . . .

  5. using: . . . . . J = 11.862242 . . . . . . . S = 29.457784 . . . . . . .
    There is an exclusive group of frequencies that have a 360 degree
    rotation characteristic. We can view these frequencies in pairs with
    these formulas:
    . . . (a) 19.8593122389 x N x 360 / (117.3017574565 x N – 360 x M)
    . . . (b) 19.8593122389 x N x 360 / (242.6982425434 x N – 360 x M)
    . . . where: 360 x M reduces the denominator so as to fall within
    . . . a range of 0 to 360 degrees

    when N = {3, 6, 9, 12, 15, . . . 132} using formula (b) we get
    2649.63297065322 years

    when N = {2, 4} using formula (b) we get 114.02975542582 years

    when N = {1, 2, 3} using formula (a) we get 60.94838271 years

    when N = {43, 86, 129, 172, . . .} using formula (a) we get
    77327.805752832 years = 1798.321064019 (43) ‘ Keeling & Whorf
    77327.805752832 years = 25775.935290544 (3) ‘ axial precession

    If we take the first N from each set we can find the root of any
    period that is derived from using formulas (a) and (b):
    2649.63297065322 / 3 = . (J / 2)(S / 5) / (J / 2 – S / 5)
    114.02975542582 / 2 = . . J (S / 3) / (J – S / 3)
    60.9483827100845 / 1 = . (S / 2) J / (S / 2 – J)
    77327.805752832 / 43 = . (S / 72)(J / 29) / (S / 72 – J / 29)

    When N = {132, 264, 396, . . .} using formula (a) we get
    246273.06727448875 years = 1865.70505510976 (132)
    1865.70505510976 (22) = 41045.51121241479 years ‘ obliquity
    246273.06727448875 / 132 = (S / 221)(J / 89) / (S / 221 – J / 89)

    The 2649.63297065322 and the 77327.805752832 year cycles
    are contained in the Fibonacci table above. They are members
    of an exclusive group of frequencies that display a 360 degree
    rotation of the sun’s outwardly directed acceleration.

    . . . . continued . . .

  6. using: . . . . . J = 11.862242 . . . . S = 29.457784 . . . . .
    . . (a) 19.8593122389 x N x 360 / (117.3017574565 x N – 360 x M)
    . . (b) 19.8593122389 x N x 360 / (242.6982425434 x N – 360 x M)
    . . . where: 360 x M reduces the denominator so as to fall within
    . . . a range of 0 to 360 degrees

    when N = {46, 92, 138, 184 . . .} using formula (b) we get
    79839.2026981547 years = 1735.6348412642 (46)
    79839.2026981547 / 46 = (J / 31)(S / 77) / (J / 31 – S / 77)

    when N = {89, 178, 267, . . . } using formula (b) we get
    4431425.94338327044742 years = 49791.302734643488 (89)
    49791.302734643488 (2) = 99582.605469286976 years ‘ earth’s eccentric orbit
    4431425.94338327044742 / 89 = (J / 60)(S / 149) / (J / 60 – S / 149)

    when N = {135, 270, 405 . . .} using formula (b) we get
    226418.1751199113 years = 1677.17166755489 (135)
    1677.17166755489 (135/2) = 113209.08755995565 years ‘ precession of perihelion
    226418.1751199113 / 135 = (J / 91)(S / 226) / (J / 91 – S / 226)

    The 79839.2026981547, 4431425.94338327044 and 226418.1751199113
    year cycles are contained in the Fibonacci table above. They are members
    of an exclusive group of frequencies that exhibit a 360 degree
    rotation of the sun’s outwardly directed acceleration.

    . . . . continued . . .

  7. . . . . . . J = 11.862242 . . . . . . . S = 29.457784 . . . . . .

    (1622.5187011493 yrs.) 224 = 363444.189057451 yrs.
    (1677.1716675548 yrs.) 135 = 226418.1751199113 yrs.
    (1735.6348412642 yrs.) 46 = 79839.2026981547 yrs.
    (1798.3210640193 yrs.) 43 = 77327.805752832 yrs.
    (1865.7050551097 yrs.) 132 = 246273.06727448875 yrs.
    (49791.302734643 yrs.) 89 = 4431425.94338327044742 yrs.

    It is widely accepted that because the Milankovic cycles describe
    motions of the earth that these cycles are “earth’s cycles”. But
    this is simply not true. The Milankovic cycles are the sole property
    of the sun and all of the sun’s satellites feel the same accelerations
    of the sun and this includes the four gas giants.

    The largest of these cycles, listed above, is the 4431425.94338327044742
    year cycle (49791.302734643 x 89). The earth’s eccentric orbit expands
    and contracts to a 99582.6054692869 year cycle (49791.302734643 x 2).
    This particular period is unique among the others because of its direct link
    to eccentricity. Where there is eccentricity there is acceleration. The
    Milankovic cycles belong to the sun and they all point to the large
    eccentricity cycle:

    where: . . . . . . . . P3 = P1 x P2 / (P1 – P2)

    . . . . . P1 . . . . . . . . . . . . . . P2 . . . . . . . . . . . . . . P3 . . . . . . . . .
    1677.1716675548 ‘ ‘ ‘ ‘ ‘ 1622.5187011493 ‘ ‘ ‘ ‘ ‘ 49791.302734643
    1735.6348412642 ‘ ‘ ‘ ‘ ‘ 1677.1716675548 ‘ ‘ ‘ ‘ ‘ 49791.302734643
    1798.3210640193 ‘ ‘ ‘ ‘ ‘ 1735.6348412642 ‘ ‘ ‘ ‘ ‘ 49791.302734643
    1865.7050551097 ‘ ‘ ‘ ‘ ‘ 1798.3210640193 ‘ ‘ ‘ ‘ ‘ 49791.302734643

    . . . . . . continued . . .

  8. OB,
    Thanks for bringing up the Saturn orbital period issue.

    I’ve commented on this in an earlier thread. I’ll just re-post
    it here so you don’t have to look for it:

    The orbital periods for Jupiter and Saturn have some irregularity about
    them, so there is a lot of disagreement about their exact values. Surprisingly
    there really isn’t as much room for tweaking these numbers as some would
    believe. The exact number of days is pretty solid, it’s the additional hours
    that are causing fights to break out. It is important that we address this
    issue before we move on.

    The best values can be found at: nssdc.gsfc.nasa.gov/planetary/factsheet
    by author Dr David R. Williams: using sidereal periods S = 29.457 and
    J = 11.862.

    Avoid using: the data at ssd.jpl.nasa.gov/?planet_phys_par
    This data had a mislabeling problem in which the tropical periods were
    listed as sidereal. An attempt to correct the problem resulted in a
    period of S = 29.447 years sidereal and S = 29.42351935 tropical.

    The Williams data at nssdc.gsfc also had a tropical period of S = 29.424
    years, suggesting that the ssd.jpl sidereal period of S = 29.447 is most
    likely a typo.

    Like I said earlier, there isn’t a lot of room for this much error. The difference
    between the sidereal values of 29.447 (ssd.jpl) and 29.457 (nssdc.gsfc)
    would be more than 3 and a half days, an obvious typo.

  9. OB,
    I don’t know where that anonymous came from.
    I’d like to hear what you have to say about the Fibonacci
    sequence.

  10. Here are some more graphs TOM MANGO has asked me to post for discussion
    Unfortunately the comment section doesn’t seem to support large pictures Tom.

    Readers may have to click on this link to the original storage point
    when the picture loads . you may have to click on it to load the larger zoomed image
    https://goo.gl/photos/ejD1y2LjFw4Jc6ZX7


    by tom mango

    or try th😓s link
    https://photos.google.com/share/AF1QipPDhiGZmzUFLOUeaWveNvd-3a8Qn5T3X6okCnDkY1Q3YhUXh8W-zMVpM9D5YoZ78Q/photo/AF1QipMdomgXaVI9ozH02RxHeyOL6Ja3hrFpb5CYm02j?key=bXB0OEhsRGZlbktQbmJRSk1kVklZQ0oyVHhDYTlR

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s